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van_damme
Orange Belt
Joined: 13 Mar 2002
Posts: 210
Location: London England
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 Posted: Sun Apr 28, 2002 8:55 am Post subject: |
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ok..i need HELP!!!..i have this maths question..and if i dont do this one..then my maths teacher is just gonna kill me...she is one of those teachers who pic on u coz ur not exactly the best student in the class...anyway..here is the question..I NEED FULL WORKING OUT IF U CAN!!!
A shop employs 8 men and 2 women
The mean weekly wage of the 10 employees is £396
The mean weekly wage of the 8 men is £400
Calculate the mean weekly wage of the 2 women?
GOOD LUCK..i need this done by 2morrow morning
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Taokara
Yellow Belt
Joined: 18 Apr 2002
Posts: 67
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| Posted: Sun Apr 28, 2002 9:02 am Post subject: |
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| All i know is that the mean is the average of something hope that helps buddy. |
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YODA
Black Belt
Joined: 25 Jan 2002
Posts: 1033
Location: England (int'north west)
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| Posted: Sun Apr 28, 2002 12:47 pm Post subject: |
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OK here goes....
To get the total mean you must have had to divide the total wages by the number of people - so mean = total / number
We know the mean (396) and the number (10) so we get -
396 = total / 10
total = 396 * 10 = 3960 (total all wages)
We can do the same for just the men...
total = 400 * 8 = 3200 (total mens wages)
So - the total wages for the women must be 3960 - 3200 = 760
There are 2 women - so their mean wage must be 760/2 = 380 ..... Tadaaaaaa!!!!
_________________
YODA
2nd Degree Black Belt : Doce Pares Eskrima www.docepares.co.uk
Qualified Instructor : JKD Concepts www.jkdc.co.uk
Qualified Fitness Instructor (Weights, CV, Circuit, Kinesiology) |
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Bon
Black Belt
Joined: 10 Aug 2001
Posts: 1047
Location: Australia
Styles: BJJ, Kickboxing
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| Posted: Sun Apr 28, 2002 8:52 pm Post subject: |
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Aw, I was hoping for a real math problem.
_________________
It takes sacrifice to be the best.
There are always two choices, two paths to take. One is easy. And its only reward is that it's easy. |
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tessone
Green Belt
Joined: 23 Apr 2002
Posts: 395
Location: Galesburg, IL
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| Posted: Sun Apr 28, 2002 8:58 pm Post subject: |
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Let G and H be groups, f:G->H be a group homomorphism, and e1 and e2 be the identity elements in G and H respectively. Then prove that f(e1) = e2. 
And a math joke:
Q: What is purple and commutes?
A: An Abelian grape.
_________________
Chris Tessone
Brown Belt, Kuk Sool Won |
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YODA
Black Belt
Joined: 25 Jan 2002
Posts: 1033
Location: England (int'north west)
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| Posted: Sun Apr 28, 2002 11:29 pm Post subject: |
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Easy peasy
f(e1) = e2. - 'cos I say so and I've got a big stick!
_________________
YODA
2nd Degree Black Belt : Doce Pares Eskrima www.docepares.co.uk
Qualified Instructor : JKD Concepts www.jkdc.co.uk
Qualified Fitness Instructor (Weights, CV, Circuit, Kinesiology) |
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tessone
Green Belt
Joined: 23 Apr 2002
Posts: 395
Location: Galesburg, IL
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| Posted: Mon Apr 29, 2002 6:46 am Post subject: |
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Hey, that's cheati--- Ahhhh!!!
*runs*
_________________
Chris Tessone
Brown Belt, Kuk Sool Won |
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van_damme
Orange Belt
Joined: 13 Mar 2002
Posts: 210
Location: London England
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| Posted: Mon Apr 29, 2002 9:53 am Post subject: |
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| Thanks for the answer..too bad my maths teacher wasnt in the leasson to actually see if you was correct..lolz |
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Deathcometh
Orange Belt
Joined: 20 Feb 2002
Posts: 198
Location: Dunlap
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| Posted: Thu May 02, 2002 8:18 am Post subject: |
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LOL..... 
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on the post.
